Voila quelques question faciles : x associe x/1+x² 1) Calculer f(-5) , f(-3) , f(-1) , f(1) , f(3) , f(5) Voila ;)

f(-5)={-5/(1+(-5)²)} = -5/26
 f(-3)={-3/(1+(-3)²)}= -3/10
, f(-1)={-1/(1+(-1)²)} = -1/2
f(1)={1/(1+(1)²)} = 1/2
, f(3)={3/(1+(3)²)}=3/10
 et f(5)={5/(1+(5)²)}= 5/26